27 EXAMPLE:
Assume single pass weld in 1/2-in. plate using single
V procedure: a. .41 lb. electrode/foot
b. 21 ipm travel speed c.
1125 amps X 36 volts = 40,500 watts d.
assume 50% or 1/2 operating factor Cost
per foot 1. Wire:
.41 x $.80/lb. =
.328 $/ft.
2. Flux:
.41 x 2 x $.70/lb =
.582 $/ft.
3. Power: 40500
/ (5000 x 21) 0.10 $/Kw hr.
= .040
$/ft. 4.
Labor: $40.00/hr. / (5
x 21 x .5) = .762
$/ft. TOTAL
= 1.71
$/ft.
